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lenient parsing of invalid single \ in regexp() function

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This commit is contained in:
tophf 2018-01-11 15:05:38 +03:00
parent 650cf3521b
commit b754635b81
1 changed files with 10 additions and 1 deletions
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11
js/moz-parser.js
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@ -16,6 +16,7 @@ function parseMozFormat({code, styleId}) {
'domain': 'domains',
'regexp': 'regexps',
};
const hasSingleEscapes = /([^\\]|^)\\([^\\]|$)/;
const parser = new parserlib.css.Parser();
const sectionStack = [{code: '', start: 0}];
const errors = [];
@ -47,7 +48,15 @@ function parseMozFormat({code, styleId}) {
}
for (const {name, expr, uri} of e.functions) {
const aType = CssToProperty[name.toLowerCase()];
(section[aType] = section[aType] || []).push(uri || expr && expr.parts[0].value || '');
const p0 = expr && expr.parts[0];
if (p0 && aType === 'regexps') {
const s = p0.text;
if (hasSingleEscapes.test(p0.text)) {
const isQuoted = (s.startsWith('"') || s.startsWith("'")) && s.endsWith(s[0]);
p0.value = isQuoted ? s.slice(1, -1) : s;
}
}
(section[aType] = section[aType] || []).push(uri || p0 && p0.value || '');
}
sectionStack.push(section);
});