2022-04-07 02:24:00 +00:00
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open Jest
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2022-04-12 23:59:40 +00:00
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open Expect
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open TestHelpers
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describe("mixture", () => {
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testAll(
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"fair mean of two normal distributions",
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list{(0.0, 1e2), (-1e1, -1e-4), (-1e1, 1e2), (-1e1, 1e1)},
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tup => {
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// should be property
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let (mean1, mean2) = tup
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let meanValue = {
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run(Mixture([(mkNormal(mean1, 9e-1), 0.5), (mkNormal(mean2, 9e-1), 0.5)]))->outputMap(
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2022-07-04 15:24:30 +00:00
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FromDist(#ToFloat(#Mean)),
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)
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}
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meanValue->unpackFloat->expect->toBeSoCloseTo((mean1 +. mean2) /. 2.0, ~digits=-1)
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},
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)
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2022-04-07 17:33:12 +00:00
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testAll(
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"weighted mean of a beta and an exponential",
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// This would not survive property testing, it was easy for me to find cases that NaN'd out.
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list{((128.0, 1.0), 2.0), ((2e-1, 64.0), 16.0), ((1e0, 1e0), 64.0)},
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tup => {
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let ((alpha, beta), rate) = tup
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let betaWeight = 0.25
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let exponentialWeight = 0.75
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let meanValue = {
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run(
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Mixture([(mkBeta(alpha, beta), betaWeight), (mkExponential(rate), exponentialWeight)]),
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)->outputMap(FromDist(#ToFloat(#Mean)))
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}
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let betaMean = 1.0 /. (1.0 +. beta /. alpha)
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let exponentialMean = 1.0 /. rate
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meanValue
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->unpackFloat
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->expect
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->toBeSoCloseTo(betaWeight *. betaMean +. exponentialWeight *. exponentialMean, ~digits=-1)
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},
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)
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testAll(
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"weighted mean of lognormal and uniform",
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// Would not survive property tests: very easy to find cases that NaN out.
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list{((-1e2, 1e1), (2e0, 1e0)), ((-1e-16, 1e-16), (1e-8, 1e0)), ((0.0, 1e0), (1e0, 1e-2))},
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tup => {
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let ((low, high), (mu, sigma)) = tup
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let uniformWeight = 0.6
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let lognormalWeight = 0.4
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let meanValue = {
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run(
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Mixture([
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(mkUniform(low, high), uniformWeight),
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(mkLognormal(mu, sigma), lognormalWeight),
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]),
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)->outputMap(FromDist(#ToFloat(#Mean)))
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}
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let uniformMean = (low +. high) /. 2.0
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let lognormalMean = mu +. sigma ** 2.0 /. 2.0
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meanValue
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->unpackFloat
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->expect
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->toBeSoCloseTo(uniformWeight *. uniformMean +. lognormalWeight *. lognormalMean, ~digits=-1)
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},
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)
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})
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