simple-squiggle/node_modules/mathjs/lib/esm/function/set/setIsSubset.js

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import { flatten, identify } from '../../utils/array.js';
import { factory } from '../../utils/factory.js';
var name = 'setIsSubset';
var dependencies = ['typed', 'size', 'subset', 'compareNatural', 'Index'];
export var createSetIsSubset = /* #__PURE__ */factory(name, dependencies, _ref => {
var {
typed,
size,
subset,
compareNatural,
Index
} = _ref;
/**
* Check whether a (multi)set is a subset of another (multi)set. (Every element of set1 is the element of set2.)
* Multi-dimension arrays will be converted to single-dimension arrays before the operation.
*
* Syntax:
*
* math.setIsSubset(set1, set2)
*
* Examples:
*
* math.setIsSubset([1, 2], [3, 4, 5, 6]) // returns false
* math.setIsSubset([3, 4], [3, 4, 5, 6]) // returns true
*
* See also:
*
* setUnion, setIntersect, setDifference
*
* @param {Array | Matrix} a1 A (multi)set
* @param {Array | Matrix} a2 A (multi)set
* @return {boolean} true | false
*/
return typed(name, {
'Array | Matrix, Array | Matrix': function ArrayMatrixArrayMatrix(a1, a2) {
if (subset(size(a1), new Index(0)) === 0) {
// empty is a subset of anything
return true;
} else if (subset(size(a2), new Index(0)) === 0) {
// anything is not a subset of empty
return false;
}
var b1 = identify(flatten(Array.isArray(a1) ? a1 : a1.toArray()).sort(compareNatural));
var b2 = identify(flatten(Array.isArray(a2) ? a2 : a2.toArray()).sort(compareNatural));
var inb2;
for (var i = 0; i < b1.length; i++) {
inb2 = false;
for (var j = 0; j < b2.length; j++) {
if (compareNatural(b1[i].value, b2[j].value) === 0 && b1[i].identifier === b2[j].identifier) {
// the identifier is always a decimal int
inb2 = true;
break;
}
}
if (inb2 === false) {
return false;
}
}
return true;
}
});
});