53 lines
1.2 KiB
Markdown
53 lines
1.2 KiB
Markdown
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<!-- Note: This file is automatically generated from source code comments. Changes made in this file will be overridden. -->
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# Function leafCount
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Gives the number of "leaf nodes" in the parse tree of the given expression
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A leaf node is one that has no subexpressions, essentially either a
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symbol or a constant. Note that `5!` has just one leaf, the '5'; the
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unary factorial operator does not add a leaf. On the other hand,
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function symbols do add leaves, so `sin(x)/cos(x)` has four leaves.
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The `simplify()` function should generally not increase the `leafCount()`
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of an expression, although currently there is no guarantee that it never
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does so. In many cases, `simplify()` reduces the leaf count.
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## Syntax
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```js
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leafCount(expr)
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```
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### Parameters
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Parameter | Type | Description
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--------- | ---- | -----------
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`expr` | Node | string | The expression to count the leaves of
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### Returns
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Type | Description
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---- | -----------
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number | The number of leaves of `expr`
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### Throws
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Type | Description
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---- | -----------
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## Examples
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```js
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math.leafCount('x') // 1
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math.leafCount(math.parse('a*d-b*c')) // 4
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math.leafCount('[a,b;c,d][0,1]') // 6
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```
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## See also
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[simplify](simplify.md)
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