# Left Trim > Trim whitespace characters from the beginning of a string.
## Usage ```javascript var ltrim = require( '@stdlib/string/left-trim' ); ``` #### ltrim( str ) Trims whitespace from the beginning of a `string`. ```javascript var out = ltrim( ' \r\n\t Beep \t\t\n ' ); // returns 'Beep \t\t\n ' ```
## Notes - Following [Unicode 6.3.0][unicode] and later, "whitespace" is defined as the following characters: `[ \\f\\n\\r\\t\\v\\u0020\\u00a0\\u1680\\u2000-\\u200a\\u2028\\u2029\\u202f\\u205f\\u3000\\ufeff]`.
## Examples ```javascript var ltrim = require( '@stdlib/string/left-trim' ); var str = ltrim( ' Whitespace ' ); // returns 'Whitespace ' str = ltrim( '\t\t\tTabs\t\t\t' ); // returns 'Tabs\t\t\t' str = ltrim( '\n\n\nNew Lines\n\n\n' ); // returns 'New Lines\n\n\n' ```
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## CLI
### Usage ```text Usage: ltrim [options] [] Options: -h, --help Print this message. -V, --version Print the package version. --split sep Delimiter for stdin data. Default: '/\\r?\\n/'. ```
### Notes - If the split separator is a [regular expression][mdn-regexp], ensure that the `split` option is either properly escaped or enclosed in quotes. ```bash # Not escaped... $ echo -n $' foo \n bar ' | ltrim --split /\r?\n/ # Escaped... $ echo -n $' foo \n bar ' | ltrim --split /\\r?\\n/ ``` - The implementation ignores trailing delimiters.
### Examples ```bash $ ltrim ' beep boop' beep boop ``` To use as a [standard stream][standard-streams], ```bash $ echo -n ' beep boop' | ltrim beep boop ``` By default, when used as a [standard stream][standard-streams], the implementation assumes newline-delimited data. To specify an alternative delimiter, set the `split` option. ```bash $ echo -n ' foo \t bar \t baz ' | ltrim --split '\t' foo bar baz ```