formatting pass.

squiggle_more.c

@@ -43,7 +43,7 @@ void sampler_parallel(double (*sampler)(uint64_t* seed), double* results, int n_
     int divisor_multiple = quotient * n_threads;
 
     // uint64_t** seeds = malloc((size_t)n_threads * sizeof(uint64_t*));
-    seed_cache_box* cache_box = (seed_cache_box*) malloc(sizeof(seed_cache_box) * (size_t)n_threads);
+    seed_cache_box* cache_box = (seed_cache_box*)malloc(sizeof(seed_cache_box) * (size_t)n_threads);
     // seed_cache_box cache_box[n_threads]; // we could use the C stack. On normal linux machines, it's 8MB ($ ulimit -s). However, it doesn't quite feel right.
     srand(1);
     for (int i = 0; i < n_threads; i++) {
@@ -72,9 +72,9 @@ void sampler_parallel(double (*sampler)(uint64_t* seed), double* results, int n_
                 // In principle, these results[j] could also result in two threads competing for the same cache line.
                 // In practice, though,
                 // a) this would happen infrequently
-                // b)            
+                // b) trying to unroll loops actually makes the code slower
+                // c) 8 results[j] are 8 doubles, which fit a cache line. If n_samples/n_threads
             }
-            
         }
     }
     for (int j = divisor_multiple; j < n_samples; j++) {
@@ -124,7 +124,7 @@ static double quickselect(int k, double xs[], int n)
 {
     // https://en.wikipedia.org/wiki/Quickselect
 
-    double *ys = malloc((size_t)n * sizeof(double));
+    double* ys = malloc((size_t)n * sizeof(double));
     memcpy(ys, xs, (size_t)n * sizeof(double));
     // ^: don't rearrange item order in the original array