Revert "tweak: to be reverted"

This reverts commit 6b05487242.
This commit is contained in:
NunoSempere 2023-05-02 11:41:23 -04:00
parent 6b05487242
commit a0734df444
3 changed files with 6 additions and 27 deletions

View File

@ -6,7 +6,7 @@
# make uninstall
## C compiler
CC=gcc # much faster compilation than gcc
CC=tcc # much faster compilation than gcc
COMPILER_FLAGS=#-g3 -Wall -Wextra -Wconversion -Wdouble-promotion -Wno-unused-parameter -Wno-unused-function -Wno-sign-conversion -fsanitize=undefined
# exclude: -fsanitize-trap, because I'm using an old version of gcc and couldn't bother getting a new one.
## ^ from <https://nullprogram.com/blog/2023/04/29/>
@ -35,7 +35,7 @@ STYLE_BLUEPRINT=webkit
FORMATTER=clang-format -i -style=$(STYLE_BLUEPRINT)
build: $(SRC)
$(CC) $(COMPILER_FLAGS) $(INCS) $(SRC) $(MPC) -o mumble $(LIBS) $(DEBUG)
$(CC) $(COMPILER_FLAGS) $(INCS) $(SRC) $(MPC) -o mumble $(LIBS)
format: $(SRC)
$(FORMATTER) $(SRC)

BIN
mumble

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@ -5,7 +5,7 @@
#include <string.h>
#include "mpc/mpc.h"
#define VERBOSE 1
#define VERBOSE 0
#define LISPVAL_ASSERT(cond, err) \
if (!(cond)) { \
return lispval_err(err); \
@ -122,12 +122,8 @@ lispval* lispval_qexpr(void)
}
// Destructor
void print_lispval_tree(lispval* v, int indent_level);
void delete_lispval(lispval* v)
{
if(v == NULL) return;
printf("\n Freeing:");
print_lispval_tree(v, 2);
switch (v->type) {
case LISPVAL_NUM:
if(VERBOSE) printf("\nFreed num");
@ -656,7 +652,7 @@ lispval* evaluate_lispval(lispval* l, lispenv* env)
// Check if this is a symbol
if(l->type == LISPVAL_SYM){
return get_from_lispenv(l->sym, env);
get_from_lispenv(l->sym, env);
}
// Evaluate the children if needed
@ -666,32 +662,16 @@ lispval* evaluate_lispval(lispval* l, lispenv* env)
}
}
// Check if any are errors.
// lispval* error = NULL;
for (int i = 0; i < l->count; i++) {
if (l->cell[i]->type == LISPVAL_ERR) {
return l->cell[i];
// error = clone_lispval(l->cell[i]);
return clone_lispval(l->cell[i]);
}
}
// Now the problem is that evlauate_lispval is recursive
// and it also allocates new memory.
// This means that I want to delete the allocated memory.
// But the problem is that it could delete the original object l
// leading to a double-free error
// To mitigate this, I've made the delete_lispval function
// a bit more robust, to be able to handle cases where it had
// already been deleted
// But the compromise here is to not care about destruction to
// the original object in case of an error.
// if(error!=NULL){
// delete_lispval(l);
// return error;
// }
// Check if the first element is an operation.
if (l->count >= 2 && ((l->cell[0])->type == LISPVAL_FUNC)) {
lispval* temp = clone_lispval(l->cell[0]);
lispval* f = pop_lispval(temp, 0);
lispval* f = pop_lispval(l, 0);
lispval* operands = temp;
// lispval* operation = clone_lispval(l->cell[0]);
// lispval* operands = lispval_sexpr();
@ -774,7 +754,6 @@ int main(int argc, char** argv)
print_lispval_parenthesis(answer);
printf("\n");
}
delete_lispval(l);
delete_lispval(answer);
} else {