fix bug by adding count to all types.
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28f94b2ee1
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2
makefile
2
makefile
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@ -6,7 +6,7 @@
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# make uninstall
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## C compiler
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CC=gcc # much faster compilation than gcc
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CC=tcc # much faster compilation than gcc
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COMPILER_FLAGS=#-g3 -Wall -Wextra -Wconversion -Wdouble-promotion -Wno-unused-parameter -Wno-unused-function -Wno-sign-conversion -fsanitize=undefined
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# exclude: -fsanitize-trap, because I'm using an old version of gcc and couldn't bother getting a new one.
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## ^ from <https://nullprogram.com/blog/2023/04/29/>
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38
src/mumble.c
38
src/mumble.c
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@ -38,6 +38,7 @@ lispval* lispval_num(double x)
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{
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lispval* v = malloc(sizeof(lispval));
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v->type = LISPVAL_NUM;
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v->count = 0;
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v->num = x;
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return v;
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}
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@ -46,6 +47,7 @@ lispval* lispval_err(char* message)
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{
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lispval* v = malloc(sizeof(lispval));
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v->type = LISPVAL_ERR;
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v->count = 0;
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v->err = malloc(strlen(message) + 1);
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strcpy(v->err, message);
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return v;
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@ -55,6 +57,7 @@ lispval* lispval_sym(char* symbol)
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{
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lispval* v = malloc(sizeof(lispval));
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v->type = LISPVAL_SYM;
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v->count = 0;
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v->sym = malloc(strlen(symbol) + 1);
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strcpy(v->sym, symbol);
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return v;
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@ -267,29 +270,44 @@ void print_ast(mpc_ast_t* ast, int indent_level)
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lispval* clone_lispval(lispval* old)
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{
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lispval* new;
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print_lispval_tree(old, 0);
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printf("\nCloning lispval of type %d\n", old->type);
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switch(old->type){
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case LISPVAL_NUM:
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printf("\n1");
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printf("\nnum: %f", old->num);
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print_lispval_tree(old, 0);
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new = lispval_num(old->num);
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printf("\nAssigned new");
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printf("\n count: %i", old->count);
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break;
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case LISPVAL_ERR:
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printf("2");
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new = lispval_err(old->err);
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break;
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case LISPVAL_SYM:
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printf("3");
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new = lispval_sym(old->sym);
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break;
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case LISPVAL_SEXPR:
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printf("4");
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new = lispval_sexpr();
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break;
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case LISPVAL_QEXPR:
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printf("\n5");
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new = lispval_qexpr();
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break;
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default:
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return lispval_err("Error: Cloning element of unknown type.");
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}
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for (int i = 0; i < old->count; i++) {
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lispval* temp_child = old->cell[i];
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lispval* child = clone_lispval(temp_child);
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lispval_append_child(new, child);
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printf("\n6");
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if(old->count > 0){
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for (int i = 0; i < old->count; i++) {
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lispval* temp_child = old->cell[i];
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lispval* child = clone_lispval(temp_child);
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lispval_append_child(new, child);
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}
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}
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return new;
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}
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@ -319,13 +337,17 @@ lispval* take_lispval(lispval* v, int i)
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// Operations
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// Ops for q-expressions
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lispval* builtin_head(lispval* v){
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printf("Entering builtin_head with v->count = %d and v->cell[0]->type = %d\n", v->count, v->cell[0]->type);
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// head { 1 2 3 }
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// But actually, that gets processd into head ({ 1 2 3 }), hence the v->cell[0]->cell[0];
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LISPVAL_ASSERT(v->count ==1, "Error: function head passed too many arguments");
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LISPVAL_ASSERT(v->count == 1, "Error: function head passed too many arguments");
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LISPVAL_ASSERT(v->cell[0]->type == LISPVAL_QEXPR, "Error: Argument passed to head is not a q-expr, i.e., a bracketed list.");
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LISPVAL_ASSERT(v->cell[0]->count != 0, "Error: Argument passed to head is {}");
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printf("Passed assertions, v->cell[0]->count = %d\n", v->cell[0]->count);
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// print_lispval_parenthesis(v);
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lispval* result = clone_lispval(v->cell[0]->cell[0]);
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print_lispval_parenthesis(v->cell[0]);
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lispval* result = clone_lispval(v->cell[0]);
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printf("Cloned lispval, result->type = %d\n", result->type);
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// lispval* result = pop_lispval(v->cell[0], 0);
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// ^ also possible
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// A bit unclear. Pop seems like it would depend on the size of the array. clone depends on the sie of head.
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@ -470,6 +492,8 @@ lispval* builtin_functions(char* func, lispval* v)
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// Evaluate the lispval
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lispval* evaluate_lispval(lispval* l)
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{
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// Check if this is an s-expression
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if(l->type != LISPVAL_SEXPR) return l;
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// Evaluate the children if needed
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for (int i = 0; i < l->count; i++) {
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if (l->cell[i]->type == LISPVAL_SEXPR) {
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