76 lines
2.9 KiB
Python
76 lines
2.9 KiB
Python
# -*- coding: utf-8 -*-
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# This file is part of the Calibre-Web (https://github.com/janeczku/calibre-web)
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# Copyright (C) 2018-2019 OzzieIsaacs, cervinko, jkrehm, bodybybuddha, ok11,
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# andy29485, idalin, Kyosfonica, wuqi, Kennyl, lemmsh,
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# falgh1, grunjol, csitko, ytils, xybydy, trasba, vrabe,
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# ruben-herold, marblepebble, JackED42, SiphonSquirrel,
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# apetresc, nanu-c, mutschler
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#
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# This program is free software: you can redistribute it and/or modify
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# it under the terms of the GNU General Public License as published by
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# the Free Software Foundation, either version 3 of the License, or
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# (at your option) any later version.
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#
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# This program is distributed in the hope that it will be useful,
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# but WITHOUT ANY WARRANTY; without even the implied warranty of
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# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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# GNU General Public License for more details.
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#
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# You should have received a copy of the GNU General Public License
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# along with this program. If not, see <http://www.gnu.org/licenses/>.
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from math import ceil
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# simple pagination for the feed
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class Pagination(object):
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def __init__(self, page, per_page, total_count):
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self.page = int(page)
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self.per_page = int(per_page)
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self.total_count = int(total_count)
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@property
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def next_offset(self):
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return int(self.page * self.per_page)
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@property
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def previous_offset(self):
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return int((self.page - 2) * self.per_page)
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@property
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def last_offset(self):
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last = int(self.total_count) - int(self.per_page)
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if last < 0:
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last = 0
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return int(last)
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@property
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def pages(self):
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return int(ceil(self.total_count / float(self.per_page)))
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@property
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def has_prev(self):
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return self.page > 1
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@property
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def has_next(self):
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return self.page < self.pages
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# right_edge: last right_edges count of all pages are shown as number, means, if 10 pages are paginated -> 9,10 shwn
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# left_edge: first left_edges count of all pages are shown as number -> 1,2 shwn
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# left_current: left_current count below current page are shown as number, means if current page 5 -> 3,4 shwn
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# left_current: right_current count above current page are shown as number, means if current page 5 -> 6,7 shwn
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def iter_pages(self, left_edge=2, left_current=2,
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right_current=4, right_edge=2):
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last = 0
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left_current = self.page - left_current - 1
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right_current = self.page + right_current + 1
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right_edge = self.pages - right_edge
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for num in range(1, (self.pages + 1)):
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if num <= left_edge or (left_current < num < right_current) or num > right_edge:
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if last + 1 != num:
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yield None
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yield num
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last = num
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