Bugfix advanced search for language
Update results from testrun
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cps/db.py
17
cps/db.py
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@ -796,23 +796,24 @@ class CalibreDB():
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def speaking_language(self, languages=None, return_all_languages=False, with_count=False, reverse_order=False):
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from . import get_locale
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if not languages:
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if with_count:
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if with_count:
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if not languages:
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languages = self.session.query(Languages, func.count('books_languages_link.book'))\
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.join(books_languages_link).join(Books)\
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.filter(self.common_filters(return_all_languages=return_all_languages)) \
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.group_by(text('books_languages_link.lang_code')).all()
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for lang in languages:
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lang[0].name = isoLanguages.get_language_name(get_locale(), lang[0].lang_code)
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return sorted(languages, key=lambda x: x[0].name, reverse=reverse_order)
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else:
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for lang in languages:
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lang[0].name = isoLanguages.get_language_name(get_locale(), lang[0].lang_code)
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return sorted(languages, key=lambda x: x[0].name, reverse=reverse_order)
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else:
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if not languages:
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languages = self.session.query(Languages) \
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.join(books_languages_link) \
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.join(Books) \
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.filter(self.common_filters(return_all_languages=return_all_languages)) \
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.group_by(text('books_languages_link.lang_code')).all()
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for lang in languages:
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lang.name = isoLanguages.get_language_name(get_locale(), lang.lang_code)
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for lang in languages:
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lang.name = isoLanguages.get_language_name(get_locale(), lang.lang_code)
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return sorted(languages, key=lambda x: x.name, reverse=reverse_order)
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